1. Determine the sample weight of crushed tablet powder needed for a 35-mL titra

Question

1. Determine the sample weight of crushed tablet powder needed for a 35-mL titration with 0.01 N KIO3. The assay is 75%, and the sample is dissolved in 100-mL of solution with a 10-mL aliquot used. 1. Determine the sample weight of crushed tablet powder needed for a 35-mL titration with 0.01 N KIO3. The assay is 75%, and the sample is dissolved in 100-mL of solution with a 10-mL aliquot used. 1. Determine the sample weight of crushed tablet powder needed for a 35-mL titration with 0.01 N KIO3. The assay is 75%, and the sample is dissolved in 100-mL of solution with a 10-mL aliquot used.

Explanation / Answer

Given that,

KIO3 = 0.01 N or eq / L

Volume – 35 mL = 0.035 L

First calculate the amount of Asc acid :

0.01 eq KIO3/ 1.0 L *0.035 L* 1 eq Asc acid / 1 eq KIO3*88.6 g Asc acid/ 1 eq

= 0.03082 g Asc acid

Assume that sample weight is X

0.03082 g/ X g = 75%

X =0.04109 g

Thus the sample weight of crushed tablet is 0.04109 g

0.03082/0.04109 *100= 75%

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