Given the unbalanced equation, for the species that is the oxidizing agent, ente

Question

Given the unbalanced equation, for the species that is the oxidizing agent, enter the symbol and the initial oxidation state of the specific element that will accept electrons.

Enter sign followed by Arabic numeral for oxidation state magnitude. Use 0 if the oxidation state is zero.

Example:

Element: P

Oxidation state: +3

Mg(s) + AuCl3(aq) ? Au(s) + MgCl2(aq)

Element:

2)

Given the balanced equation, enter the formula and state of the product that formed as a result of its precursor donating electrons. If more than one answer exists, separate by a comma.

Ca(s) + 2H2O(l) ? Ca2+(aq) + 2OH-(aq) + H2(g)

3)

Given the unbalanced equation, for the species that forms as a result of accepting electrons, enter the symbol and the final oxidation state of the specific element that was reduced. Use arabic numerals for oxidation state magnitude.

Example:

Element: Sb

Oxidation state: 0

Cd(s) + H+(aq) + ClO4-(aq) ? Cd2+(aq) + ClO4-(aq) + H2(g)

Element:

4)

Given the unbalanced equation, for the species that is the oxidation product, enter the symbol and the final oxidation state of the specific element that has a higher oxidation state. Use arabic numerals for oxidation state magnitude.

Example:

Element: Na

Oxidation state: +1

Li(s) + H2O(l) ? Li+(aq) + OH-(aq) + H2(g

Element:

Oxidation state:

5)

Given the unbalanced equation, for the species that is the oxidation product, enter the symbol and the final oxidation state of the specific element that donated electrons. Use arabic numerals for oxidation state magnitude. If more than one answer exists, enter in the order they meet in the reaction separating by a comma.

Example:

Element: S,C

Oxidation state: +2,+4

Co(s) + HNO3(aq) ? Co(NO3)2(aq) + NO(g) + H2O(l)

Element:

Oxidation state:

6)

Given the balanced equation, enter the formula and state of the product that formed as a result of the oxidation of its precursor (oxidation product). If more than one answer exists, separate by a comma.

6Sr(s) + P4(s) ? 2Sr3P2(s)

Explanation / Answer

1) Mg(s) + AuCl3(aq) Au(s) + MgCl2(aq)

Element:Mg

Oxidation state: 0 to +2 (gives out 2 electrons)[oxidation]

Element :Au

Oxidation state:+3 to 0(accepts 3 e-)[reduction]

2)

Ca(s) + 2H2O(l) Ca2+(aq) + 2OH-(aq) + H2(g)

Ca -2e Ca2+

2H2O 2OH- + 2H+

2H+ 2eH2

the product that formed as a result of its precursor donating electrons=H2

3)

Cd(s) + H+(aq) + ClO4-(aq) Cd2+(aq) + ClO4-(aq) + H2(g)

Element:H

Oxidation state:+1 to 0 (2H+ +e H2)

4)

Li(s) + H2O(l) Li+(aq) + OH-(aq) + H2(g

Element:Li

Oxidation state:0 to +1

5)

Co(s) + HNO3(aq) Co(NO3)2(aq) + NO(g) + H2O(l)

Element:Co

Oxidation state:0 to +2

6)

6Sr(s) + P4(s) 2Sr3P2(s)

Oxidation product :Sr2+ (Sr -2e-Sr2+)

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