Explain how the following changes would affect the rate of the reaction of 2-bro

Question

Explain how the following changes would affect the rate of the reaction of 2-bromo-2-methylbutane with methanol: The alkyl halide is changed to 2-iodo-2-methylbutane. The reaction will be faster because the leaving group will be better. The reaction will be slower because the leaving group will be poorer. The reaction will be slower because the leaving group will be better. The rate of the reaction does not change. The alkyl halide is changed to 2-chloro-3-methylbutane. The reaction will be slower because it will be an Sn2 reaction with a poor nucleophile. The reaction will be faster because it will be an Sn2 reaction with a poor nucleophile. The reaction will be faster because it will be an Sn2 reaction with a good nucleophile. The rate of the reaction does not change.

Explanation / Answer

Part A (weak bases are good leaving groups)

The alkyl halide 2-iodo-2-methylbutane contains weaker base. I- is a weaker base than Br-, So Rate of reaction will be fater because the leaving group is better..

Part B

The reaction will be slower because it will be an SN2 reaction with a poor nucleophile

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