P1.16 Chlorofluorocarbons (CFCs) have been widely used as refrigerants. They ey
ID: 1002777 • Letter: P
Question
P1.16 Chlorofluorocarbons (CFCs) have been widely used as refrigerants. They ey are nontoxic and stable. But their are particularly attractive because th stability means that they persist for a long time in the atmosphere. CFC have been linked to depetio he upper ozone layer. Some researchers. ave been linked to depletion of the upper ozone layer. Some researchers have proposed destroying CFCs by reaction with sodium oxalate (Na2C20,) to produce three solids: sodium fluoride (NaF), sodium chlo- ride (NaCI), and coke (C), along with CO2 gas. Write the stoichiometri- cally balanced chemical equation for destruction of one CFC IFreon-12. CF C2] with sodium oxalate. Calculate the g CFC Freon F2C12] with sodium oxalate. Calculate the grams of sodium oxalate required, and the total grams of solid products produced, per gram of Freon-12 destroyed.Explanation / Answer
Stoichiometric equation for the destruction of CFCs i.e. Freon–12 (CF2Cl2) using sodium oxalate Na2C2O4.
CF2Cl2 . + 2 Na2C2O4. ----------> 2NaF + 2NaCl + C + 4CO2 (g)
Stoichiometry says, mole equivalence is,
1 moles CF2Cl2 2 moles Na2C2O4 2 moles NaF 2 moles NaCl 1 mole C 4 mol CO2.
Molar masses of above species,
Molar mass of CF2Cl2 = 120.91 g
Molar mass of Na2C2O4 = 134 g
Molar mass of NaF = 41.99 g
Molar mass of NaCl = 58.44 g
Atomic mass of C = 12.01 g
Molar mass of CO2 = 44.01 g
Hence we write mass equivalence is given as,
120.91 g CF2Cl2 2 x 134 g Na2C2O4 2 x 41.99 g NaF 2 x 58.44 g NaCl 12.01 g C 4 x 44.01 g CO2.
I.e. 120.91 g CF2Cl2 268 g Na2C2O4 83.98 g NaF 116.88 g NaCl 12.01 g C 176.04 g CO2. ………………(1)
We want the mass of Na2C2O4 required for destruction of 1 g of CF2Cl2 and also the solid products formed.
Hence we divide the above equivalence with molar mass of CF2Cl2 i.e. 120.91 through.
Hence we write,
(120.91/120.91) g CF2Cl2 (268/120.91) g Na2C2O4 (83.98/120.91) g NaF (116.88/120.91) g NaCl (12.01/120.91) g C.
1 g CF2Cl2 2.217 g Na2C2O4 0.695 g NaF 0.967 g NaCl 0.099 g C
Hence we get answer as,
2.217 g Na2C2O4 for destruction of 1 g CF2Cl2.
And destruction of 1 g Freon–12 gives 0.695 g NaF, 0.967 g NaCl and 0.099 g C.
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