If a student added the dried pure KHP crystals to the volumetric flask, a few cr

Question

If a student added the dried pure KHP crystals to the volumetric flask, a few crystals spill on the floor. If the student continues to prepare the solution, will the calculated concentration of this solution be higher, lower or equal to the actual concentration? Explain how you determined your answer. If a student added the dried pure KHP crystals to the volumetric flask, a few crystals spill on the floor. If the student continues to prepare the solution, will the calculated concentration of this solution be higher, lower or equal to the actual concentration? Explain how you determined your answer.

Explanation / Answer

Now we are adding KHP crystals to the certain volume of solution which means we are adding certain moles of KHP in L litres of solution.Concentration= moles of solute(KHP added)/ volume of solution in litres.

Now since some crystals spill on floor so the moles added to solution decreases and as moles of solute is in numerator so by the formula Concentration= moles of solute(KHP added)/ volume of solution in litres., the concentration will be lower than expected or actual.

concentration(actual) = moles of solute(KHP added)/ volume of solution in litres

experimental after error = (( moles of solute(KHP added))- (moles of crystal spilled))/ total volume of solution.

decrease in numerator decreases concentration.

If we add the moles of KHP spill on floor the numerator we can get back correct value.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.