Write a balanced chemical equation for the reaction of hydrochloric acid with ca

Question

Write a balanced chemical equation for the reaction of hydrochloric acid with calcium hydroxide. Include states of reactants and products. Equation: Ca(OH)_2 + 2HCl rightarrow CaCl_2 + 2H_2 O Data and Results: Molarity of hydrochloric acid .050 M .050M Volume of hydrochloric acid 10.00 mL 10.00 mL Initial buret reading .30 mL 0.00 mL Final buret reading 17.60 mL 17.20 mL Volume calcium hydroxide used 17.30 mL 17.20 mL .017 L .017 L Moles hydrochloric acid used .0005 moles .0005 moles Moles calcium hydroxide used____moles____moles Concentration of calcium hydroxide__M___M Average Concentration of calcium hydroxide___M

Explanation / Answer

Ca(oh)2 + 2 hcL ----> cAcL2 + H2O

1 MOL Ca(oh)2 = 2 mol HCl

No of mol of HcL used = 0.005 mol

so that

nO of mol of Ca(Oh)2 recated = 0.005/2 = 0.0025 mol

trail 1

Concentration of Ca(OH)2 = 0.0025/0.0173 = 0.144 M

trail 2

Concentration of Ca(OH)2 = 0.0025/0.0173 = 0.144 M

average Concentration of Ca(OH)2 = 0.144+0.144/2 = 0.144 M

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