13,6. PLEASE ANSWER CORRECTLY. I HAVE POSTED THIS QUESTION 3 TIMES AND GOT WRONG

Question

13,6.

PLEASE ANSWER CORRECTLY. I HAVE POSTED THIS QUESTION 3 TIMES AND GOT WRONG ANSWERS. WILL LEAVE FEEDBACK.

Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is 2 AlBr3(s)2 Al(s) +3 Br2(l) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) Al(s) + 3/2 Br2(l)Alr3(s) 2) 2 Al(s) +3 Br2(l)2 AlBr3(s) 3) AlBrj(s) Al(s) +3/2 Br2(l) K3 =

Explanation / Answer

1)   k1 = (1/k)^(1/2)

2) K2 = (1/K)

3) k3 = k^(1/2)

2.

k = (1/ka)* kb^2

3. k1 = (1/k)^2

   k2 = (1/k)

   k3 = k^2

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.