1) What is the definition of the Enthalpy of Reaction? A) The amount of heat in

Question

1) What is the definition of the Enthalpy of Reaction?

A) The amount of heat in kJ released (exothermic) or gained (andothermic) per mole of product.

B) The amount of heat in Joules require to evaporate 1 mole of reactant.

C) The amount of energy released from gaseous expansion during a reaction.

2) Which of the following reactions needs to be reversed to solve for the Heat of Neutralization between Hydrochloric Acid and Ammonia?

A) Hydrochloric Acid + Sodium Hydroxide.

B) Acetic Acid + Sodium Hydroxide.

C) Acetic Acid + Ammonia.

3) What is the molar heat of neutralization (Enthalpy of Reaction) in kJ/mol if 5 moles of HA neutralized 5 moles of BOH and released 13619 J of heat?

4) Calculate the molar heat of neutralization in kJ/mol of the reaction between HA and BOH given the following information:

The temperature change equals 5C,
50 mL of 1 M concentration of Acid
50 mL of 1 M concentration of Base
Heat capacity of the calorimeter is 6.5 J/C.
Remember that the specific heat of water is 4.18 J/gC

5) How much heat is gained (in Joules) by the water where a chemical reaction takes place in 100 mL aqueous solution and has a temperature increase of 11 C?

Explanation / Answer

1)A

2)C

3)if 5 moles of acid and base reacted 13619J of heat is released

For 1 mole ,13619/5= 2.7238kJ/ mole

4) given 1*50"10^-3 =0.05moles reacted

Temp diff= 5c

For dilute solutions of acid and base , volume =mass

Therefore mass of acid =50g

Mass of base= 50 g

Total mass = 100 g

Heat released ,q = mcpt

= 100*4.18*5= 2090j

Heat of neutralization for 0.05 moles = 2090/0.05=41800J=41.8kJ

5) heat gained =mcpt=100*4.18*11=4598J

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