1. According to the following reaction, how many grams of chlorine gas are requi

Question

1.

According to the following reaction, how many grams of chlorine gas are required for the complete reaction of 25.5 grams of iron?

iron (s) + chlorine (g) iron(III) chloride (s)

_____grams chlorine gas

2.

According to the following reaction, how many grams of ethane (C2H6) will be formed upon the complete reaction of 27.7 grams of ethylene (C2H4) with excess hydrogen gas?

hydrogen (g) + ethylene (C2H4) (g) ethane (C2H6) (g)

______grams ethane (C2H6)

3.

For the following reaction, 4.76 grams of diphosphorus pentoxide are mixed with excess water . The reaction yields 4.46 grams of phosphoric acid .

diphosphorus pentoxide ( s ) + water ( l ) phosphoric acid ( aq )

What is the theoretical yield of phosphoric acid ? ____grams
What is the percent yield for this reaction ? ______%

4.

For the following reaction, 3.87 grams of iron are mixed with excess chlorine gas . The reaction yields 9.88 grams of iron(III) chloride .

iron ( s ) + chlorine ( g ) iron(III) chloride ( s )

What is the theoretical yield of iron(III) chloride ?_____ grams
What is the percent yield for this reaction ?_____ %

Explanation / Answer

2Fe + 3Cl2 (g) ------> 2FeCl3

2 moles of Fe react with 3 moles of Cl2

2*56g of Fe react with 3*71g of Cl2

25.5g of Fe react with = 3*71*25.5/2*56 = 48.5g of Cl2.

2.

C2H4 + H2 -------> C2H6

1 mole of C2H4 react with H2 to form 1 mole of C2H6

28g of C2H4 react with H2 to form 30g of C2H6

27.7g of C2h4 react with h2 to form = 30*27.7/28 = 29.67g of C2H6

3.

P2O5 + 3H2O ------>2H3PO4

1 mole of P2O5 react with H2O to form 2 moles of H3PO4

142g of P2O5 react with H2O to form 2*98g of H3PO4

4.76g of P2O5 react with H2O to form = 2*98*4.76/142 = 6.57g of H3PO4

theoretical yield of phosphoric acid = 6.57g of H3PO4

pecentage yield = Actual yield*100/theoretical yield

                             = 4.46*100/6.57 = 67.88%

4. 2Fe + 3Cl2 (g) ------> 2FeCl3

2 moles of Fe react with Cl2 to form 2 moles of FeCl3

2*56g of Fe react with to form 2*162g of FeCl3

3.87g of react with to form = 2*162*3.87/2*56 = 11.2g of FeCl3

pecentage yield = Actual yield*100/theoretical yield

                            = 9.88*100/11.2 = 88.21%

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