Consider a photon that exists in another galaxy at a distance of 1.8 times 10^14

Question

Consider a photon that exists in another galaxy at a distance of 1.8 times 10^14 cm from earth. If it takes 3.3 times 10^-9 seconds for light to travel a distance of 1 cm, how many seconds will it takes for the photon to travel from its current position to earth? 5.5 times 10^26 1.8 times 10^18 5.9 times 10^9 1.8 times 10^-27 If the density of air under ordinary conditions is 1.19 g/L, how many kilograms of air will be found in an ordinary room that measures 11.0 ft times 11.0 ft and has a 10.0 ft ceiling? (1 in, = 2.54 cm, 1 ft = 12 in.) 0.0366 3.66 0.152 4.08 times 10^4 40.8

Explanation / Answer

2) distance = 1.8*10^18 cm

   light velocity = 3.03*10^8 cm/sec

time required = 1.8*10^18/(3.03*10^8) = 5.9*10^9 sec

anser: c

3) volume of the room

11 ft = 335.28 cm

10 ft =

= 335.28*335.28*304.8

= 3.43*10^4 L

mass of air in room = 3.43*10^4*1.19 = 4.08*10^4 grams

answer: d

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