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Part D A 1.4 kg block of iron at 30 C is rapidly heated by a torch such that 11

ID: 1010309 • Letter: P

Question

Part D

A 1.4 kg block of iron at 30 C is rapidly heated by a torch such that 11 kJ is transferred to it. What temperature would the block of iron reach assuming the complete transfer of heat and no loss to the surroundings? If the same amount of heat was quickly transferred to a 890 g pellet of copper at 22 C, what temperature would it reach before losing heat to the surroundings?

qcs, Fe(s)cs, Cu(s)===mcsT0.450 J/gC0.385 J/gC

Express the final temperatures of the iron and copper in C to two significant figures separated by a comma.

Final temperatures of Fe, Cu =

Explanation / Answer

For 1.4 kg Fe

q = mCpdT

with,

q = 11 kJ

m = 1.4 kg = 1400 g

Cp = 0.450 J/g.oC

dT = Tf - 30 oC

Tf is the final temperature

we get,

11000 = 1400 x 0.450 x (Tf - 30)

Tf = 47.46 oC

For Copper = 890 g

Cp = 0.385 J/g/oC

we get,

11000 = 890 x 0.385 x (Tf - 22)

Tf = 54.10 oC

Final temperatures of Fe,Cu = 47.46 oC , 54.10 oC

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