A voltaic cell contains two half-cells. One half-cell contains a gold electrode

Question

A voltaic cell contains two half-cells. One half-cell contains a gold electrode immersed In a 1.00 M Au(NO_3)_3 solution. The second half-cell contains a copper electrode immersed in a 1.00 M Cu(NO_3)_2 solution. Au^3+ (aq) + 3 e^- rightarrow Au(s) E^ red = +1.498 V Cu^2+(aq) + 2e^- rightarrow Cu(s) E^ red = +0.342 V Using the standard reduction potentials given above, predict the standard cell potential of the voltaic cell. Write the overall balanced equation for the voltaic cell. (Include states-of-matter under the given conditions in your answer.)

Explanation / Answer

a)

E0 cell = Eredox half cell - E oxidation half cell

in the given reduction potentials which is having the least value thaty will under go oxidation

E0 cell = 1.498 v - 0.342 v

E0 cell = 1.156 v

part B

3Cu (s) + 2Au3+ (aq) ---> 2Au (s) + 3Cu2+ (aq)

  

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