A voltaic cell contains two half-cells. One half-cell contains a gold electrode

Question

A voltaic cell contains two half-cells. One half-cell contains a gold electrode immersed in a 1.00 M Au(NO3)3 solution. The second half-cell contains a zinc electrode immersed in a 1.00 M Zn(NO3)2 solution.

Au3+(aq) + 3 e Au(s) Ered = +1.498 V

Zn2+(aq) + 2 e Zn(s) Ered = 0.762 V

(a) Using the standard reduction potentials given above, predict the standard cell potential of the voltaic cell. ______ V

(b) Write the overall balanced equation for the voltaic cell. (Include states-of-matter under the given conditions in your answer.)

Explanation / Answer

a)

standard reduction potentials = Eo cathode - Eo anode

                                               = 1.498 + 0.762

                                             = 2.260 V

b) overall balanced equation :

3 Zn (s) + 2 Au3+ (aq) -------------------------> 3 Zn2+(aq) + 2 Au (s)

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