Due tomorrow morning, need help thank you in advance. Charge in coulombs= 267 nu
ID: 1010547 • Letter: D
Question
Due tomorrow morning, need help thank you in advance.
Charge in coulombs= 267
number of moles of electrons= .00277
1(a) Use the stoichiometry of the cathode reaction to determine the expected number of moles of hydrogen gas, based upon the number of moles of electrons passed through the circuit.
(b) Use the stoichiometry of the anode reaction to determine the expected number of moles of copper oxidized, based upon the number of moles of electrons passed through the circuit.
2(a) If the inital buret reading is 50.00 mL and the final reading is 5.16 mL determine the volume of hydrogen gas produced. (buret is upsidedown)
(b) Determine the pressure of the hydrogen gas collected (in atm) at 298K, given the height of the remaining column of liquid in the buret was measured to be 139 mm and the barometric pressure aas 741.6 mmHg. You will need to refer to data in table below:
Note: P(H2) = P (barometric) - P (hydrostatic) - P(H2O) and P (hydrostatic) = (height of liquid in buret in mm) / (13.6 mm H2O/ mmHg)
(C) use the ideal gas law to fin the number of moles of hydrogen gas. 5. If the initial mass of the anode was 22.814 g and the final mass was 22.724 g,determine the number of moles of copper oxidized.
3(a) Calculate the 'electrochemical' percent yield of hydrogen gas.
(b) Calculate the electrochemical percent yield of coppor oxidized.
Temperature (C) Pressure (mmHg) Temperature (C) Pressure (mmHg) 16 13.6 22 19.8 17 14.5 23 21.2 18 15.5 24 22.4 19 16.5 25 23.8 20 17.5 26 25.2 21 18.5 27 26.7Explanation / Answer
1a)
number of moles of electron, n = 0.00277 mol
2H+ +2e- ---> H2
number of moles of H2 = 0.00277/2 = 0.001385 mol
b)
Cu2+ + 2e- ---> Cu
number of moles of Cu = 0.00277/2 = 0.001385 mol
I am allowed to answer only 1 question at a time
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