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Write the equation for each metal combination indicating which metal is being ox

ID: 1010713 • Letter: W

Question

Write the equation for each metal combination indicating which metal is being oxidized and which metal is being reduced. Using the Table above calculate the E E^o_cell for Zn(s)|Zn^2+(aq)||Cu^2+(aq)|Cu(s) Show your work. Using the Nernst equation calculate the E for the cell when Zn^2+ (aq) = 0.10 M and Cu^2+ (aq) = 0.10M Show your work. How does your value in answer #3 compare to what you measured? Using the Nernst equation calculate the E for the cell when Zn^2+ (aq) = 0.10 M and Cu^2+ (aq) = 0.001 M Show your work. How does your value in answer #5 above compare to what you measured? E^o_cell = E^o_cathode - E^o_anode Nernst Equation E = E^o_cell - 0.059/n Times log Q

Explanation / Answer

1) we know that

oxidation takes place at anode

reduction takes place at cathode

so

a) Zn + Cu+2 --> Zn+2 + Cu

oxidized --> Zn

reduced --> Cu+2

b)

3Zn + 2Al+3 --> 3Zn+2 + 2Al

oxidized --> Zn

reduced --> Al+3

c)

Zn + Pb+2 --> Zn+2 + Pb

oxidized --> Zn

reduced --> Pb+2

d) Pb + Cu+2 --> Pb+2 + Cu

oxidized --> Pb

reduced --> Cu+2

e)

3Pb + 2Al+3 --> 3Pb+2 + 2Al

oxidized --> Pb

reduced --> Al+3


f)

3 Cu + 2 Al+3 --> 3 Cu+2 + 2Al

oxidized --> Cu

reduced --> Al+3

g)

Zn + Cu+2 --> Zn+2 + Cu

oxidized --> Zn

reduced --> Cu+2

2)

we know that

Eo cell = Eo cathode - Eo anode

Eo cell = Eo Cu+2/Cu - Eo Zn+2/Zn

Eo cell = 0.34 + 0.76

Eo cell = 1.1

so

the value of Eo cell is 1.1


3)


the reaction is

Zn (s) + Cu+2 (aq) --> Zn+2 (aq) + Cu (s)

the reaction quotient is given by

Q = [Zn+2] / [Cu+2]

Q = 0.1 / 0.1

Q = 1

no2

E = Eocell - (0.059/n) log Q

E = 1.1- (0.059/2) log 1

E = 1.1 V

so

the value of Ecell is 1.1 V

4)

the obtained value is 0.835 V

so

the obtained value is less than the theoretical value

5)


Q = [Zn+2] / [Cu+2]

Q = 0.1 / 0.001

Q = 100

now

E = 1.1 - (0.059/2) log 100

E = 1.041

so

the E cell value is 1.041 V


6)

the obtained value is 0.782 V

so

the obtained value is less than the theoretical value