Consider the reaction: 2 A (g) + B (g) C (g) + 2 D (g) k_p = 0.60 at 25 degree C

Question

Consider the reaction: 2 A (g) + B (g) C (g) + 2 D (g) k_p = 0.60 at 25 degree C. What is the value of k_P for the reaction 3 C (g) + 6 D (g) 6 A (g) + 3 B (g) ? A. 4.63 B. 1.80 C. 0.216 D. 5.00 E. 4.80 18. For a reaction, a plot of In k (rate constant) vs. 1/T (kelvin temperature) gave a line with slope - 2440 kelvin and y - intercept 5.50. What is the energy of activation for the reaction? A. 24.40 kJ B. 13.42 kJ C. 15.40 kJ D. 20.29 kJ E. 97.30 kJ 19. You are titrating 25.00 ml of 0.200 M HOAc with 0.200 M NaOH. What is the pH at the equivalence point of the titration, that is after addition of 25.00 ml of NaOH? (k_a of HOAc = 1.80 times 10^-5) HOAc + NaOH NaOAc + H_2O A. 7.00 B. 5.13 C. 8.87 D. 7.20 E. 9.05

Explanation / Answer

17) 2A + B ---> C + 2D .......(1)

Kp = 0.6

The other reaction is

3C + 6D ---> 6A + 3B .....(2)

Equation (2) = -3 X equation (1)

Kp(2) = 1/ Kp(2)3

Kp(2) = 1/ (0.6)^3 = 4.63

18)

If a plto for lnK with 1/T is plotted then the equation is for arrhenius equation

lnk=EaRT+lnA

Slope = -Ea/R = -2440 Kelvin

Ea = 2440 X R= 2440 X 8.314 X 10^-3 = 20.29 KJ

19)

The pH at equivalence point will be above 7 and near 8.87

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