For the vaporization of benzene, Hvap = 30.7 kJ/mol and Svap = 87.0 J/(Kmol). Pa

Question

For the vaporization of benzene, Hvap = 30.7 kJ/mol and Svap = 87.0 J/(Kmol).

Part A Calculate Ssurr and Stotal at 66 C. Ssurr = J/K

Part B Express your answer using two significant figures. Stotal = J/K

Part C Calculate Ssurr and Stotal at 80 C. Ssurr = J/K

Part D Stotal = J/K

Part E Calculate Ssurr and Stotal at 91 C.

Part F Express your answer using two significant figures.

Part G Does benzene boil at 66 C and 1 atm pressure?

Does benzene boil at 66  and 1 atm pressure?

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Part H

Calculate the normal boiling point of benzene.

Express your answer using two significant figures.

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Explanation / Answer

a)
Ssurrounding = -Q/T = heat given up by surroundings / temp.
Ssurrounding at the temp. 66°C = (-30700 J/mol) / 339.15K = -90.52 J/mol K

Stotal at the temp. 66°C = -90.52 J/mol K + 87.0 J/mol K = -3.52 J/molK

C) Ssurrounding at the temp. 80°C = (-30700 J/mol) / 353.15K = -86.9 J/mol K

Stotal at the temp. 80°C = -86.9 J/mol K + 87.0 J/mol K = 0.07 J/molK

e) Ssurrounding at the temp 91°C = (-30700 J/mol) / 364.15K = -84.306 J/mol K
Ssystem = 87.0 J/mol K
Stotal at the temp 91°C = -84.306 J/mol K + 87.0 J/mol K = 2.694 J/mol K

f) 2.69

G) no.. the Stotal is negative at T = 66°C. think about that implication

h) at normal bp.. G = 0.. and since G = H - TS... T = H/S = (30700 J/mol) / (87.0 J/mol K) = 352.9K = 79.7°C

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