If a stove top can deliver the equivalence of 2 times 10^6 Joules per hour in en

Question

If a stove top can deliver the equivalence of 2 times 10^6 Joules per hour in energy to a pot of water (specific heat capacity 4.18 J/g degree C, density of water 1g/ml, volume of water 1.5L), about how long will it take to raise the temperature of the water from 20 degree C to 90 degree C? 13 minutes 26 minutes 439 minutes 0.219 minutes If the stove top tries to heat the same amount (in mass) of oil (heat capacity 2.0 L/g degree C) as in problem 23 on the same stove top, then the time it take to heat the oil 70 degrees will be approximately 4.18/2.0 * answer to #23 2.0/4.18 * answer to #23 4.18/2.0*70 * answer to #23 2.0/(4.18*70) * answer to #23 If a 15 gram piece of aluminum metal (specific heat capacity 0.902 J/g degree C) at 110 degree C is dropped into 45 grams of ethylene glycol (specific heat capacity 2.200 J/g degree C) at 60 degree C what is the final temperature of the ethylene glycol? -87 degree C 66 degree C 87 degree C 116 degree C If the pH value of 0.05M HCl is 1.30, then the pH of H_2SO_4 must be (Note: The K, value for HCl and the K_a1 value for H_2SO_4 are both very large; the K_a2 for HSO_4^- iS 1.3 times 10^-2, you can estimate the answer without using the quadratic formula!) 1.30 2.60 1.00 1.23

Explanation / Answer

23. a

q = m x c x delta T

m = volume x density

m = 1500 g

q = 1500 x 4.18 x (70)

q = 438900 J

time = 438900 / 2x106 = 0.219 h = 13 minutes

24. b

q = 1500 x 2.0 x (50)

q = 150000 J

time = 150000 J / 2x106 = 0.075 h = 4.5 minutes

25. b

m1 x c1 x delta T = m2 x c2 x delta T

15g x 0.902 x (110 - T2) = 45 x 2.20 x (T2 - 60 )

1488.3 - 13.53 T2 = 99 T2 - 5940

112.53 T2 = 7428.3

T2 = 66 0C

26. a

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