In the neutralization of 50.0 mL of 0.1 M BOH (a weak base with Kb = 1.6 x 10-7)

Question

In the neutralization of 50.0 mL of 0.1 M BOH (a weak base with Kb = 1.6 x 10-7) with 0.10 M H2SO4, the most correct description of the solution at the mid-point of the titration, i.e., half neutralized, is:

a solution in which [B+] essentially equals [BOH]

a solution in which [B+] essentially equals 4 x 10-4 M

a solution whose volume is 75 mL and contains some undissociated BOH molecules and some B+, OH-, and HSO4- ions

a solution containing SO42- and B2+ ions

a solution in contact with BSO4 solid

Explanation / Answer

In the neutralisation reaction of base BOH with H2SO4, half-equivalence point would have,

a solution in which [B+] essentially equals to [BOH]

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