For a spontaneous reaction A(aq) + B(aq) rightarrow A^-(aq) + B^+(aq) answer the

Question

For a spontaneous reaction A(aq) + B(aq) rightarrow A^-(aq) + B^+(aq) answer the following questions: If you made a voltaic cell out of this reaction, what half-reaction would be occurring at the cathode, and what half-reaction would be occurring at the anode? A(aq) + 1e^- rightarrow A^-(aq)at the cathode and B(aq) rightarrow B^+ (aq) + 1e^- at the anode A(aq) + 1e^- rightarrow A^-(aq)at the anode and B(aq) rightarrow B^+ (aq) + 1e^- at the cathode Which half-reaction from part above is higher in potential energy? The anode reaction is higher in potential energy. The cathode reaction is higher in potential energy. What is the sign of E^degree cell? E^degree_cell is positive. E^degree_cell is negative.

Explanation / Answer

Part A)

option 1 : A(aq) + 1 e- ----> A- (aq) at cathode, B(aq) -------> B+(aq) + e- at anode.

Anode: positively charged terminal - oxidation reaction.
Cathode: negatively charged terminal - reduction reaction

Part B)

option 2 : The cathode reaction is higher in potential energy.

For spontaneous reaction Ecell must be positive. Ecell = Ecathode - Eanode.

To be positive Ecell , Ecathode must be higher.

Part C)

option 1: Eocell is positive.

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