4.30x 10 Record the measured absorbance for each tube in the following table. Co

Question

4.30x 10 Record the measured absorbance for each tube in the following table. Complete the table by calculating the [Fe(SCN2 Je, and the [Fe'J and the [HSCNJntsa. Iustrate these using data from tube 2 Report the IFe(SCN hg to one more digit than that allowed by applying the rules of significant figures 0.115-(4.30 x 103)o A= kc 0.055(20 x(0)c C 1.28 x 105 2.014 x10 G 4.372 0.500 0.500 0.500 0.500 0.500 50,188 ,312 10 2.5 xto 0 Determine the [Fe leq. [HSCNl [Hl and Keg for each tube. This is best done by constructing an 'ICE' table and using it to find the asked for equilibrium concentrations. The equilibrium constant is found using equation 2. (See the TREATMENT OF DATA section for an example.) Tube 1 ICE ta Keqt HSCN 1 10.0 x10 O,500 b.128 x101 Tube 2 ICE table: Tube 3 ICE table: Keas

Explanation / Answer

table1 As [HSCN]initial is not given ,so i just consider it to be 2.0*10^-4 to show calculations

tube 1

Keq=[FeSCN2+][H+]/[Fe3+][SCN-]

ICE table Fe3+ +HSCN --->FeSCN2+ +H+

[FeSCN2+]=1.279*10^-5M=x

keq1=(1.279*10^-5M)(0.500)/(2.372*10^-4M)(1.872*10^-4)=1.44*10^2

[Fe3+] [HSCN] [FeSCN2+] [H+] initial 2.5*10^-4M 2.0*10^-4M 0 0.500M change -x -x +x +x equilibrium 2.5*10^-4M-x 2.0*10^-4M-x x x reverse equilibrium rxn 2.372*10^-4M 1.872*10^-4 1.279*10^-5M 0.500

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