11. An adult takes about 15 breathes per minute with each breath having a volume
ID: 1025920 • Letter: 1
Question
11. An adult takes about 15 breathes per minute with each breath having a volume of 500 mL. If the air that is inhaled is dry, but exhaled at 1 atm is saturated with water vapor at 37°C, what is t mass of water lost from the body in one hour. The vapor pressure of water at 37°C is 47.1 torr 12. Magnesium and aluminum react with acid to give hydrogen gas. What volume of hydrogen gas measured at 25°C and a pressure of 0.985 atm can be obtained from 4.00 g of an alloy that is 20.0 % Mg and 70.0 % AI? 2 H, (aq) 6H+ (aq) H2 (g) + Mg+2 (aq) 3H2 (g) + 2A1+3(aq) Mg (s) + 2Al(s) + 13. A mixture contained calcium carbonate and magnesium carbonate. A sample of this mixture weighing 7.85 g was reacted with excess hydrochloric acid. If the sample reacted completely and produced 1.94 L of carbon dioxide at 25°C, and 785 mmHg, what are the percentages of calcium carbonate and magnesium carbonate in the sample?Explanation / Answer
Hi i am sorry to say as per Chegg Guidelines to Experts we can answer only 1 full question that too 1st question.
The volume of air inhaled in 1 hour is (since we have to calculate mass of water lost per hour)
(60 min/hr)(15 breath/min)(0.500L/breath) = 450 L
To find moles of H2O, use the Ideal Gas Law:
PV = nRT
1 torr = 0.00131579 atm
47.1 torr = 0.06197368 atm
P = 0.06197368 atm for water vapor
R = 0.082057 L.atm/K.mol
T = 273 + 37 = 310K
Find moles of H2O:
n = PV / RT = (0.06197368 atm)(450 L) / (0.082057 L.atm/K.mol)(310K)
n = 1.09633295817 moles
Mass of H2O in grams is: (moles H2O)(molar mass of H2O)
(1.09633295817 mol)(18.015 g/mol.H2O) = 19.8 grams (3 significant figures)
Mass of water lost from the body in one hour = 9.8 grams (3 significant figures)
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