Can u do 1,2,4 Study GuideChapter 8 CHE 103/Spring, 2018 Read: sec. 8.1-8.11 Omi

Question

Can u do 1,2,4 Study GuideChapter 8 CHE 103/Spring, 2018 Read: sec. 8.1-8.11 Omit sections 8.12-14 Know: Chapter Goals p. 247 Homework problems 8.34, 8.35, 8.36, 8.37, 8.38, 8.42, 8.46, 8.48, 8.62, 8.63, 8.65, 8.69, 8.80, 8.82, 8.84 2. Problems to be done in class Chapter 8 1. A barometer has a pressure reading of 600 torr. Convert this pressure to units atm (atmospheres) and Pa (Pascals). 2. An O2 cylinder used for breathing has a volume of 5.0L at 90 atm pressure. Wh volume would the same amount of oxygen have, if the pressure was at 1.0 atm. (Assume the temperature is the same.) Moll 3. Calculate the number of moles of air in the lungs of a person with a total lung capacity of3.4. Assume that the person is at 1.0 atm pressure and has a normal body temperature of 37°C. 4. An aerosol spray deodorant can with a volume of 350 mL contains 3.2 g of propane gas (CsHs) as propellant. What is the pressure in the can at 20°C? molar mass of CF4 = 44.11 g/mol, R-0.0821 L Atm/moLK

Explanation / Answer

1)

600 torr x 1 atm / 760 torr = 0.78947 atm

600 torr = 0.78947 atm x 101325 Pa / 1 atm = 79993.4 pascal

2)

for gases PV = nRT

when amount of gas and temperature are constant

PV = constant

so

P1V1 = P2V2

90 atm x 5 L = 1 atm x V2

V2 = 450 L

so

the volume would be 450 L

3)

moles of gas (n) = 3.2 g / (44.11 g/mol) = 0.0725459 mol

volume (V) = 350 ml = 0.35 L

temperature (T) = 20 + 273 K = 293 K

PV = nRT

plug in the values

P x 0.35 L = 0.0725459 mol x 0.0821 ( L atm /mol K) x 293 K

P = 4.986 atm

so

the pressure is 4.986 atm

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