Calculate the number of micrograms of protein for each of the standard assay tub

Question

Calculate the number of micrograms of protein for each of the standard assay tubes and add the these values 1. Protocol for Bradford Assay Standard Curve (1 pt) Prepare a table (Table 1a) for your protocol for setting up a standard curve. The protein standard is approximately 1 mg/ml of bovine serum albumin (BSA). The standard assay protocol should look like the one below, which indicates the volume of protein standard (BSA) and water to add to each test tube. Calculate the number of g protein for each of the standard assay tubes and add these values to your table 1a. These tubes should contain protein levels in the range of 0-50 ug. Test Tube 1 2 3 45 67 05 10 20 30 40 50 Protein Standard (1.0 mg/ml or g/W) Water 100 95 90 80 70 60 50 g protein in assay

Explanation / Answer

Volume of standard BSA taken = 0.0 uL

Amount of protein taken = Volume of BSA standard taken x [Protein] in std. BSA

                                                            = 0.0 uL x (1.0 ug/ uL)

                                                            = 0.0 ug

Therefore, total mass of protein in tube 2 = 0.0 ug

Volume of standard BSA taken = 5.0 uL

Amount of protein taken = Volume of BSA standard taken x [Protein] in std. BSA

                                                            = 5.0 uL x (1.0 ug/ uL)

                                                            = 5.0 ug

Therefore, total mass of protein in tube 2 = 5.0 ug

Volume of standard BSA taken = 10.0 uL

Amount of protein taken = Volume of BSA standard taken x [Protein] in std. BSA

                                                            =10.0 uL x (1.0 ug/ uL)

                                                            = 10.0 ug

Therefore, total mass of protein in tube 2 = 10.0 ug

Volume of standard BSA taken = 20.0 uL

Amount of protein taken = Volume of BSA standard taken x [Protein] in std. BSA

                                                            =20.0 uL x (1.0 ug/ uL)

                                                            = 20.0 ug

Therefore, total mass of protein in tube 2 = 20.0 ug

Volume of standard BSA taken = 30.0 uL

Amount of protein taken = Volume of BSA standard taken x [Protein] in std. BSA

                                                            =30.0 uL x (1.0 ug/ uL)

                                                            = 30.0 ug

Therefore, total mass of protein in tube 2 = 30.0 ug

Volume of standard BSA taken = 40.0 uL

Amount of protein taken = Volume of BSA standard taken x [Protein] in std. BSA

                                                            =40.0 uL x (1.0 ug/ uL)

                                                            = 40.0 ug

Therefore, total mass of protein in tube 2 = 40.0 ug

Volume of standard BSA taken = 50.0 uL

Amount of protein taken = Volume of BSA standard taken x [Protein] in std. BSA

                                                            =50.0 uL x (1.0 ug/ uL)

                                                            = 50.0 ug

Therefore, total mass of protein in tube 2 = 50.0 ug

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