2. A 2.60-g sample of titanium chemically combines with chlorine gas to form 10.
ID: 1026478 • Letter: 2
Question
2. A 2.60-g sample of titanium chemically combines with chlorine gas to form 10.31 g of a titanium chloride a. What is the empirical formula of titanium chloride? le le 0 d, b. What is the percent by mass of titanium and the percent by mass of chlorine in the sample? 3. a. Experimental Procedure, Part A. List two reasons for using crucible tongs to handle the crucible and lid after their initial firing. b. Why is it best to cool the crucible and lid (and sample) in a desiccator rather than on the laboratory bench? 15bExplanation / Answer
2)a)
mass of titanium chloride = 10.31 g
mass of titanium = 2.60 g
mass of Chloride = 10.31 - 2.60 = 7.71 g
moles of Ti = 2.60 / 47.87 = 0.054
moles of Cl = 7.71 / 36.5 = 0.21
simplest ratio
Ti = 0.054 / 0.054 = 1.0
Cl = 0.21 / 0.054 = 4.0
3)a)
. A crucible is used to fire a sample,the method is used to determine difference between the unfired sample and the fired sample. So in order to accuire accurate result it is advisable to use crusible tongs. The crusible tongs are designed in such a manner for easy handling of crusible while its hot, thus minimizes the chances of accident due to burning and falling of crusible
As crusible doesn't look that hot, but it is used for the sample firing, so its always advisable to use crusible tongs for safe handling. If crusible handled after initial firing with bare hands, or with latex gloves it may burn the handler.
b. The cooling of the crubile is preferred in desiccator only as by placing the crusible on bench may cause fire or handler may get burned. In order to obtain the accurate result after firing it is advisable to keep the sample as isolated as possible to avoid contamination. Thus cooling the crusible in desiccator is advisable.
empirical formula = TiCl4
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