Use the References to access important values if needed for this question The fo
ID: 1026827 • Letter: U
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Use the References to access important values if needed for this question The following thermochemical equation is for the reaction of hydrogen sulfide(g) with water() to form hydrogen(g) and sulfur dioxide(g) When 11.7 grams of hydrogen sulfide(g) react with excess water() kJ of energy are is absorbed or amount of energy is expressed as a postive sumber. The sign of AH in the thermochemical equation indicat evolved evolved. absorbed Retry Entire Group 4 more group attempts remaining Submit AnswerExplanation / Answer
H2S is the limiting reactant, according to the stoichiometry 1 mole of H2S has H = 207 kJ
moles of H2S = 11.7 gms / 34.1 gm/mol = 0.3431 mol
1 mole of H2S has H = 207 kJ
0.3431 mol of H2S has H = + 71.0217 kJ per mole
When 11.7 gms of H2S reacts with excess water 71.0217 kJ of energy are absorbed.
moles of ethane = 11.5gm / 30.07 gm/mol = 0.38244 mol
But according to the reaction,
2 moles of C2H6 gives H = - 2.86*103 kJ
0.38244 mol of C2H6 gives H = (-2.86*103kJ)*0.38244 / 2 = -546.8892 kJ per mole
When 11.5 gms of C2H6 reacts with excess O2 -546.8892 kJ of energy are evolved.
Heat lost by lead = - (Heat gained by water)
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