I need help in rewrite it To begin with, the characteristic properties of the qu

Question

I need help in rewrite it

To begin with, the characteristic properties of the quadruple bonds and the electron configuration is that they are very strong but short bonds. They have interesting spectroscopic characteristics such as their bright colors. Mo2(O2CCH3) is a bright yellow and K4Mo2Cl8×2H2O has a bright magenta color which is due to the d to d* transition. They can also decompose if in air too long.

In each of these compounds, the Mo2 will have a charge of +4 and a total number of electron valence shell of 12 which equates to 8 electrons (4 bonding molecular orbitals). The four d orbitals occupied are s (dz2), p (dxz, dyz), d (dxy).

Unfortunately, due to equipment and time, the experiment did yeild the highest and best compounds. The only IR that was able to be down was of Mo2(O2CCH3)4. The IR (3001 cm, 2357 cm -1, 2165 cm -1, and 2023) showed one similar peak (3001 cm-1) similar to molybdenum stretching bond. The final product Mo2Cl4 [P(C4H9) 3]4 was not able to dissolve in chloroform so no NMR was able to be completed.

Some errors may have started since the first synthesis since it was left to sit in a flask for a week. The reaction could have started decomposing, which resulted in such a small yield of (approx. 6%). Another issue that may have arised was during the last synthesis of Mo2Cl4 [P(C4H9) 3]4. During filtering, the reaction flask was dropping resulting in a drop of product. The small amount of final product was not able to be characterized.

Explanation / Answer

Initially, the characteristic properties of the quadruple bonds and the electronic configuration is that they are very strong but, short bonds. They possess some spectroscopic properties like bright colors. Mo2(O2CCH3) and K4Mo2Cl8.2H2O are bright yellow and magenta in color due to d-d* transition. They gets decomposed in air if kept for for a long period of time. Both the compounds have Mo2 with +4 charge and a total of 12 electron valence shell which equates to 8 electrons or 4 bonding molecular orbitals. The 4 occupied d-orbitals are s (dz2), p (dxz, dyz) and d (dxy).

Unfortunately, the experiment yields are highest and the best compounds due to equipment and time. The IR of only Mo2(O2CCH3) was able to be down. This IR (3001 cm-1, 2357 cm-1, 2165 cm-1 and 2023 cm-1) showed one peak similar to that of molybdenum stretching bond. The final product (Mo2Cl4[P(C4H9)3]4) was unable to dissolve in chloroform and hence, no NMR could be completed.

Since it was left to sit in a flask for a week, some errors may have begun as it was the first synthesis. The reaction resulted in such a small yield (approx. 6%) because it might have started decomposing. Another issue that may have arised was during the last synthesis of Mo2Cl4[P(C4H9)3]4. During filteration, the reaction flask was dropping which resulted in a drop of product. The small amount of final product was unable to be characterized.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.