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Question 2 In the production of a drug, the product stream (P) from the reactor

ID: 1027956 • Letter: Q

Question

Question 2 In the production of a drug, the product stream (P) from the reactor flows at a rate of 10.3 L/min. The final drug concentration in the product stream is 41.2% (m/m) and the remainder is water. The relative density of the product stream solution is 1.025, If the drug has a molecular weight of 192 kg/kmol, 2.1 Draw a block flow diagram, Label it appropriately and conduct a degree of freedom analysis calculate 2.2 the mass of the drug in one min of the product (kg drug/min) 2.3 the mass of the drug in one liter of the product (kg drug/L solution) 2.4 the flow rate of the drug in kmol/min.

Explanation / Answer

2.2

Flow rate of Product stream = 10.3 L/min

Mass Flow Rate of Product Stream = 10.3 x 1.025 = 10.5575 g/min

Mass Flow Rate of Product Stream = 0.01056 kg/min

Mass of drug in one min of the product = 0.01056 x 0.412 = 0.004351 kg drug/min

2.3

Product Flow rate = 10.3 L/min

Drug Flow rate = 0.004351 kg drug/min

Drug Flow rate = 0.004351 / 10.3 = 4.2243 x 10-4 kg drug / L solution

2.4

Drug Flow rate = 0.004351 kg drug/min

Drug Flow rate = 0.004351 / 192 = 2.266 x 10-5 kmol/min

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