compou centration of Sr(OH)2 Recall that poor, n 01S for every S.(OH)2 molecule

Question

compou centration of Sr(OH)2 Recall that poor, n 01S for every S.(OH)2 molecule that dissociate DL Ton wll be twice the given con Part C Calculate (OH ] for 2 010 g of LiOH in 300 0 ml of solution Express your answer using four significant figures. [OH ] 10.55 Submit Incorrect; One attempt remaining: Try Again This value is the pOH of the solution. However, the question asks for the [OH ] The |OH ] is based on t chemical formula of the compound, the concentration of the solution, and to what extent the compound will d solution. Recall that pOHlog[OH D This question will be shown after you complete previous question (s)

Explanation / Answer

Answer:-

The LiOH molar mass = 23.95 g/mole

First we calculate the number of mole of LiOH using the molar mass of LiOH

Number of mole LiOH = 2.010 g × (1 mol / 23.95g) = 0.0839 mole= OH- mole

Then convert ml into L

300 mL= 0.300 L

Therefore we calculate the molarity of LiOH

Molarity = number of moles / solution volume in liters

[OH-] = 0.0839moles / 0.300 L = 0.280 mol/L or M

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