Fe2+(aq) + 2e-= Fe(s) E-0.447 V 2H+(aq) + 2e- H2(g) E\' = 0.000 V what is Eoce\"
ID: 1028460 • Letter: F
Question
Fe2+(aq) + 2e-= Fe(s) E-0.447 V 2H+(aq) + 2e- H2(g) E' = 0.000 V what is Eoce" (in V)? Report your answer to two three decimal places in standard notation (Le., 0.123V). O.447 You are correct. Your receipt no. is 162-2547 The electrochemical cell is comprised of a Fe electrode in a 4.40 x 10-2 M solution of Fe2+ (aq) coupled to a Pt electrode in a solution containing H+ (aq) where the pH of the olution is 2.20 and the partial pressure of H2(9) is 1.700 atm. The temperature of the cell is held constant at 25°C a)What is Ecell (in V) for the electrochemical cell? Report your answer to three decimal places in standard notation (i.e., 0.123 V) 0.350 V You are correct. Your receipt no. is 162-5676Previous Tries b) If the pH of the the cell compartment on the right is increased to 3.68 while the other partial pressures and concentrations remain the same as in question 2, what will be the ew Ecell (in V)? Report your answer to three decimal places in standard notation (i.e., 0.123 V) 0.123 V) Submit Answer Tries 0/3Explanation / Answer
pH of cell compartment on right side i.e (H+/H2) is increased to 3.68 with constant partial pressure and concnetration.
EH+/H2 = EOH+/H2 +(RT/nF) In (H+/PH2)
EH+/H2 = EOH+/H2 - ( 0.059/2) 2pH
EOH+/H2 = 0.00 V
EH+/H2 = - 0.059 X pH = - 0.059 X 3.68 = 0.217 V
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