https //tamu.blac. Sociology: Race L oWLv2 | Online t Use the References to acce

Question

https //tamu.blac. Sociology: Race L oWLv2 | Online t Use the References to access important values if needed for this question. For the following reaction, 33.2 grams of hydrochlorie acid are allowed to react with 66.3 grams of barium hydroxide. hydrochloric acid(aq)+ barium hydroxide(aq) barium chloride(aq)+ wateru) What is the maximum amount of barium chloride that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams Submit Answer Retry Entire Group 9 more group attempts remaining 0 F8

Explanation / Answer

Balanced equation is

2 HCl + Ba(OH)2 ..............> BaCl2 + 2 H2O

2 mole HCl react with one mole Ba(OH)2 to form one mole BaCl2 and 2 mole H2O.

33.2 gm HCl = mass / molar mass = 33.2 / 36.5 = 0.909 mole.

66.3 gm Ba(OH)2 = 66.3 / 171.34 = 0.387 mole.

Ba(OH)2 is the limiting reactant.

maximum amount of BaCl2 formed = 0.387 mole = 0.387 * 208.23 = 80.59 gm

Excess reagent (HCl) = (0.909 - 0.387 * 2) = 0.135 mole = 0.135 * 36.5 = 4.93 gm

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