Experiment 10 Prelaboratory Assignment Vinegar Analysis Lab Sec. Name Assuming t

Question

Experiment 10 Prelaboratory Assignment Vinegar Analysis Lab Sec. Name Assuming the density ofa5% ac tic acidby mass solution is 1.0 g mL determine the volume ofthe Desk No. ion necessary to neutralize 25.0 ml, of 0.10 M NaOH. Also record this calculation on your Report Sheet. etic acid solu- 2, a A chemist often uses a whit e card with a black mark to aid in reading the meniscus of a clear liquid. How does this technique make the reading more accurate? Explain. 16a b. A chemist should wait 10-15 seconds after dispensing a volume of titrant before a reading is made. Explain why the wait is good laboratory technique 16e c. The color change at the endpoint should persist for 30 seconds. Explain why the time lapse is a good titration technique. 3. Lemon juice has a pH of about 2.5. Assuming that the acidity of lemon juice is due by mass. solely to citric acid, that citric acid is a monoprotic acid, and that the density of lemon juice is 1.0 g/mL, then the citric acid concentration calculates to 0.5% Estimate the volume of 0.0100 M NaOH required to neutralize a 3.7 lemon juice. The molar mass of citric acid is 190.12 g/mol. 1-g sample of Experiment 10 145

Explanation / Answer

(1)

molarity of acetic acid solution: 5% = 50g/litre
Molar mass acetic acid = 60.05 g mol1
Molarity = 50/60.05 = 0.833M

Balanced equation = CH3COOH + NaOH CH3COONa + H2O
Molar ratio = 1:1
Use equation:
M1V1 = M2V2
0.833 *V1 = 25*0.1
V1 = 2.5/0.833
V1 = 3.00ml

Volume of acetic acid required = 3.0ml

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