A ALEKS-Dalton McCom. xv Chegg Study l Guided S x\" C ALEKS-Dalton McCon ! } Sec
ID: 1031028 • Letter: A
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A ALEKS-Dalton McCom. xv Chegg Study l Guided S x" C ALEKS-Dalton McCon ! } Secure https://www-awh.aleks.com/alekscgi/x/Isl.exe/1o_u-lgNslkr7j8P3jH-lijk6J-TZh4JYC7viz6_juOtYisau7L4e3uhc7YwKAGUN5qluqFNHNd_MWvpqlD81mgK6plvE4E-M1Mg-xJp.. O ENTROPY AND FREE ENERGY Using reaction free energy to predict equilibrium composition Dalton Consider the following equilibrium: 2NH 3 (g-N2 (g) + 3H2 (g) Go=34. kJ Now suppose a reaction vessel is filled with 9.86 atm of ammonia (NH3) and 3.64 atm of nitrogen (N2) at 406·°C Answer the following questions about this system alo rise Under these conditions, wll the pressure or NH2 tend to rise or fall? Ar O fall Is it possible to reverse this tendency by adding H2? In other words, ir you sald the pressure of NH3 wll tend to rise, can that be changed to a tendency to fall by adding H2? Similarly, if you said the pressure or NH3 will tend to fall, can that be changed to a tendency to rise by adding H2? If you said the tendency can be reversed in the second question, calculate the minimum pressure of H, needed to reverse it. Round your answer to 2 significant digits. yes no atm Check A6:12Explanation / Answer
1. Under these conditions, the pressure of NH3 will tend to fall.
Reason: pNH3 = 9.86, pN2 = 3.64, pH2 = 3*pN2 =3*3.64 = 10.92
k = {[pN2][pH2]3}/[ pNH3]2
= (3.64)(10.92)3/(9.86)2 = 48.75
lnk = ln 48.75 = 3.89, delta G = -RTlnK = -8.314*679*48.75 = - 275.203 KJ/mol
Which means it is spontaneous in the forward direction. So NH3 on reactants side would be consumed and hence pressure of NH3 falls.
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