Ammonium vanadium(III) sulfate,(NH4)V(SO4)2 12H2O, is being prepared: Ammonium m

Question

Ammonium vanadium(III) sulfate,(NH4)V(SO4)2 12H2O, is being prepared: Ammonium metavanadate, NH4VO3, is reduced by sulfur dioxide to vanadium(IV) as the vanadyl ion. This is then reduced by electrolysis to vanadium(III).

1) what is the coordination geometry about the vanadium ion in crystals of the alum? Alum is a class of compound, what is the general formula of an alum? give 2 examples.

2) write balanced equations for each reduction step.

3) assuming an average current of 1.75 amps is passed during the electrolysis, how long it would take to reduce all V(IV) to V(III)?

4) what species is being oxidised at the anode, what species results from this oxidation?

Explanation / Answer

1. Coordination geometry of vanadium ion in the crystal is 2

NH4[V(SO4)2] . 12 H2O

General formula of alum

M2SO4, T2(SO4)3 .24 H2O.; M = MONOVALENT CATION, T = TRIVALENT CATION

EXAMPLE = K2SO4, Al2(SO4)3 .24 H2O. and K2SO4, Cr2(SO4)3 .24 H2O.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.