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H16HW 03r26/18 10 Question (4 points) a See page 816 A basic solution contains t

ID: 1032484 • Letter: H

Question

H16HW 03r26/18 10 Question (4 points) a See page 816 A basic solution contains the lodide and phosphate ions that are to be separated via selective precipitation Thercocentration, which is 970×10 s M is 10,000 times less than that of the PO-in ato.970M A solution containing the silver(l) ion is slowly added.Answer the questions below Kp of Agl is 8.30-10 17 and of Ag POs8.90x101 1st attempt Part 1 (1 point) i See Periodic Table See Hint Calculate the minimum Ags" concentration required to cause precipitation of Agl mol /L 1017> O P

Explanation / Answer

Selective precipitation

Part 1.

minimum [Ag+] needed to precipitate AgI

= Ksp/[I-]

= 8.3 x 10^-17/9.7 x 10^-5

= 8.56 x 10^-13 M

Part 2,

minimum [Ag+] needed to precipitate Ag3PO4

= cube rt(Ksp/[PO4^3-])

= cube rt(8.9 x 10^-17/0.970)

= 4.51 x 10^-6 M

Part 3,

salt to precipitate first is the one with lowest Ksp value,

AgI

Part 4,

[I-] when Ag3PO4 begins to precipitate = 8.3 x 10^-17/4.51 x 10^-6 = 1.84 x 10^-11 M

amount [I-] remained in solution = (1.84 x 10^-11) x 100/9.7 x 10^-5 = 1.89 x 10^-5%

so amunt [I-] precipitated = almost 100% (quantitative)

So,

Is the separation of the remaining ion less than 0.10%,

Yes