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1.In a population of deer a single gene controls the coat coloration trait. Of t

ID: 10329 • Letter: 1

Question

1.In a population of deer a single gene controls the coat coloration trait. Of the 20 deer in this population 4 of them express a recessive purple hair trait while the rest express the normal brown. Calculate the p and q values for the dominant allele (brown hair) and the recessive allele (purple hair) using the Hardy-Weinberg equations (p + q = 1 and p2 + 2pq + q2 = 1). Show your work.
2. After several years on the island the population has grown; however, p and q values for the hair color trait have remained the same. Name three of the five conditions needed for the Hardy-Weinberg equilibrium.

Explanation / Answer

1.In a population of deer a single gene controls the coat coloration trait. Of the 20 deer in this population 4 of them express a recessive purple hair trait while the rest express the normal brown. Calculate the p and q values for the dominant allele (brown hair) and the recessive allele (purple hair) using the Hardy-Weinberg equations (p + q = 1 and p2 + 2pq + q2 = 1). Show your work.

recessive purple hair trait --- allele=q

brown ------allele--          p

Population size =total= 20

p2 + 2pq= 16

q2 = 4

4 of them express a recessive purple hair trait= q2 = 4

q2 = 4/20= 1/5= 0.2

q= sqaure root of 0.2= 0.44

p + q = 1

p = 1----0.44= 0.56

Genotype

Frequencies

p2

0.56 x0.56            x20

6.27 around to 6

2pq

2 x0.56 x 0.44          x20

9.85 around to 10

q2

0.44 x0.44              x20

3.87 around to 10


2. After several years on the island the population has grown; however, p and q values for the hair color trait have remained the same. Name three of the five conditions needed for the Hardy-Weinberg equilibrium.

Absence of all evolutionart forces like 1.Mutations , natural selection , 3. Genetic drift etcc.,

4. random mating

5.initially sex ratios

Genotype

Frequencies

p2

0.56 x0.56            x20

6.27 around to 6

2pq

2 x0.56 x 0.44          x20

9.85 around to 10

q2

0.44 x0.44              x20

3.87 around to 10

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