the web.. rning.com/ibiscms/mod/ibis/view.php?id-5005888 Sapling Learning | Macm

Question

the web.. rning.com/ibiscms/mod/ibis/view.php?id-5005888 Sapling Learning | Macmillan L. elp sowELA Technical Commu. × PrintCalculatorPeriodic Table Question 18 of 32 Map Sapling Learning Enough of a monoprotic acid is dissolved in water to produce a 0.0194 M solution. The pH of the resulting solution is 2.53. Calculate the Ka for the acid. Number A,-114.48×10-4. There is a hint available! View the hint b bottom divider on the on the divider bar again to hide the hint. Close ONext eCheck Answer Previous ?Give Up & View Sohdon Hirt

Explanation / Answer

pH = 2.53

[H+] = 10^-2.53 = 2.95 x 10^-3 M

concentraiton = 0.0194 M

HA   ---------------> H+   +   A-

0.0194                    0           0

0.0194 - x               x             x

x = [H+] = 2.95 x 10^-3

Ka = x^2 / 0.0194 - x

     = (2.95 x 10^-3)^2 / 0.0194 - 2.95 x 10^-3

Ka = 5.30 x 10^-4

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.