A 0.181 g piece of solid aluminum reacts with gaseous oxygen from the atmosphere
ID: 1033676 • Letter: A
Question
A 0.181 g piece of solid aluminum reacts with gaseous oxygen from the atmosphere to form solid aluminum oxide. In the laboratory, student weighs the mass of the aluminum oxide collected from this reaction as 0.199g. The 0.181 g solid aluminum is the? The 0.199 g aluminum oxide is the? The gaseous oxygen is the: What is the percent yield of this reaction? A 0.181 g piece of solid aluminum reacts with gaseous oxygen from the atmosphere to form solid aluminum oxide. In the laboratory, student weighs the mass of the aluminum oxide collected from this reaction as 0.199g. The 0.181 g solid aluminum is the? The 0.199 g aluminum oxide is the? The gaseous oxygen is the: What is the percent yield of this reaction? The 0.181 g solid aluminum is the? The 0.199 g aluminum oxide is the? The gaseous oxygen is the: What is the percent yield of this reaction?Explanation / Answer
Balanced equation:
4 Al + 3 O2 ====> 2 Al2O3
Reaction type: synthesis
0.181 g solid aluminum = 0.181 / 26.98 = 0.006708 Moles
Moles of Al2O3 produced = 0.0033541 Moles
Mass of Aluminium Oxide = 0.0033541 x 101.96 = 0.34199 gm
Thoretical yield of aluminium oxide = 0.34199 gm
Actual yield of aluminium oxide = 0.199 gm
Percentage yield = 0.199 x 100 / 0.34199 = 58.18 %
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