9. A 0.5 M solution of the dissociated sodium salt of a polymer, Na\'P, is place

Question

9. A 0.5 M solution of the dissociated sodium salt of a polymer, Na'P, is placed in the left compartment, 0.3 M NaCl is placed in the right compartment, and the compartments are in contact through a semipermeable membrane, which permits diffusion of Na* and Cl, but not P. In order to reach equilibrium. (A) Na' will move from left to right and Cr will move from right to left. (B) Na will move from right to left and Cr will move from left to right (C) Both Na and Cr will move from left to right. (D) Both Na and Clr wll move from right to left.

Explanation / Answer

Osmotic pressure is a colligative property , hence depends only on the number of particles and not the nature of particles.

Number of Na+ ions in the left compartment = 0.5 moles ( Let the volume be 1L)

In the right compartment 0.3 M NaCl is present , which dissociate as Na+ (0.3M) and Cl- (0.3M).

Hence, total number of ions = 0.3 +0.3 = 0.6 moles

Now concentration of permeable ions is more in right compartment.

Hence to reach equilibrium both Na+ and Cl- will move from right to left. Option D

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