C Chapter 06 Item 6 Constants Periods Tebe The standard heat of formation, ?H-is

Question

C Chapter 06 Item 6 Constants Periods Tebe The standard heat of formation, ?H-is defined as the For which of the folowing reactions is AHequal to AH of the products)? You do not need to look up any valoes to answor this question Check all that apply View Available Hins of one mole of states Thus values can be used to calculate the enthalpy change of any reaction Consider, for example, the reaction with heat of formation values given by the folowing table ? Na(s)+] C4(1)-?NaCl(s) ? Na(s) + Cl2(g)--NaCl(s) AH? (kJ/mol O2(a) NO () 332 ??7(products)-. 2(33.2) ?? ??7(reactants) 12(90.2) Part B

Explanation / Answer

Hf means the heat of formation = change in enthalpy when 1 mole of product form it's constituents elements

-->reaction 1 S(s) + O2(g) = SO2(g) here 1-mole product is formed and from its constituent elements. here Hf = Hr

---> reaction 2 Na(s) + 1/2Cl2(l) = NaCl(s) here Cl2 is in liquid state it should be in gaseous state so Hf is not equal to Hr

----> reaction 3 Na(s) + 1/2Cl2(g) = NaCl (s) here Hf = Hr

---> reaction 4 SO(g) + 1/2 O2(g) = SO2(g) here So2 is not formed from its constituent elements SO is not elemental state. Hf is not equal to Hr

---->reaction 5 2Na(s) + Cl2(g) = 2NaCl(s) here 2 mole of product is formed so Hf is not equal to Hr

-----> reaction 6 SO3(g) = 1/2O2(g) + SO2(g) here product are not formed from elemental state . Hf is not equal to Hr.

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