I am struggling with these dilution problems. I cannot remember how to calculate

Question

I am struggling with these dilution problems. I cannot remember how to calculate them.

C) 2.50 × 102 L aminophen? D) 36.0 L E)2.50 × 102 mL 24) How much water must be added mL of a 3.00 M HCI solution solution that is-2.00 M? "on to obtain a to obtain a oht zinc ercent zine ZnS A) 7.50 × 102 mL B) 2.50 × 102 mL C) 1.00 L D) 12.0 L E) 1.50 L 03 nO 25) In order to prepare a 0.0500 M NaOH solution, to what volume would you dilute 25.0 mL of 2.50 M NaOH? 04 A) 0.0625 L B) 1.25 L C) 1.25 mI D) 0.500 L E) 1.25 x 103 L of 26) If 50.0 mL of 0.235 M NaCl solution is diluted to 200.0 mL, what is the concentration of the diluted solution? A) 0.0426 M B) 58.8 M C) 1.18 M D) 0.0588 M E) 0.0118 M

Explanation / Answer

24)

use dilution formula

M1*V1 = M2*V2

1---> is for stock solution

2---> is for diluted solution

Given:

M1 = 3.0 M

M2 = 2.0 M

V1 = 500.0 mL

use:

M1*V1 = M2*V2

V2 = (M1 * V1) / M2

V2 = (3*500)/2

V2 = 750 mL

volume of water added = V2 - V1

= 750 mL - 500 mL

= 250 mL

Answer: B

25)

use dilution formula

M1*V1 = M2*V2

1---> is for stock solution

2---> is for diluted solution

Given:

M1 = 2.5 M

M2 = 0.05 M

V1 = 25.0 mL

use:

M1*V1 = M2*V2

V2 = (M1 * V1) / M2

V2 = (2.5*25)/0.05

V2 = 1250 mL

V2 = 1.25 L

Answer: 1.25 L

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