3, working with standard values (Appendix C of text): (a) Appendix c lists the s
ID: 1036787 • Letter: 3
Question
3, working with standard values (Appendix C of text): (a) Appendix c lists the standard entropy of both 1iquid and gaseous (b) Use this and other standard entropies to calculate as for: (c) Use standard entropies to calculate AS for: (d) Use standard Gibbs energies of formation to calculate AG° for: CH. What is the entropy of the liquid form? 3C.H. (g) ?.?. ( 1 ) + 6H (g). HNO (g) + NH:(g) NH NO (s) P,010 (s) + 16 H2(g) ? 4 PH:(g) + 10 H,O(g). 4. In standard conditions, is reaction #3d spontaneous?Explanation / Answer
3. (a) Entropy of liquid form of C6H6 = 173.3 J/mol.K
(b) ?So = 173.3 + 6 x 130.7 – 3 x 200.9 = 354.8 J/mol.K
(c) ?So = 151.1 - 266.3 + 192.3 = 77.1 J/mol.K
(d) ?Go = 4 x 25.5 + (10 x -228.6) – (-2675.2) + 16 x 0 = 491.5 kJ/mol
4. The reaction #3d is not spontaneous as the Gibbs energy is positive.
Name
Standard entropies S° / (J/mol.K)
C6H6 (liquid)
173.3
C2H6 (gas)
200.9
H2 (gas)
130.7
HNO3(g)
266.3
NH3(g)
192.3
NH4NO3 (s)
151.1
Standard Gibbs energies G° / (kJ/mol)
P4O10(s)
-2675.2
H2(g)
0
PH3(g)
25.5
H2O(g)
-228.6
Name
Standard entropies S° / (J/mol.K)
C6H6 (liquid)
173.3
C2H6 (gas)
200.9
H2 (gas)
130.7
HNO3(g)
266.3
NH3(g)
192.3
NH4NO3 (s)
151.1
Standard Gibbs energies G° / (kJ/mol)
P4O10(s)
-2675.2
H2(g)
0
PH3(g)
25.5
H2O(g)
-228.6
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