? ?51b75695d57ce6982441 eaf5b6884f2# 1 0001 ne ew2offset-next&assignmentProblemi

Question

? ?51b75695d57ce6982441 eaf5b6884f2# 1 0001 ne ew2offset-next&assignmentProblemiD-97504534; 2 of 14 Part A You need to produce a buffer solption that has a pH of 5.11. You already have a solution that contains 10, mmol (millimoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? The pKa of acetic acid is 4.74 Express your answer numerically in millimoles. View Available Hint(s) mmol acetate Submit Next > rovide Feedback

Explanation / Answer

Solution:-

5.11 = 4.74 + log x / 10

5.11 - 4.74 = log x/10

0.37 = log x /10

10^0.37 = 2.34

2.34 = x / 10
x = 23.4

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