Will anything precipitate if 500.0 mL of 1.0 x 10 –8 M silver(I) nitrate 500.0 m

ID: 1038159 • Letter: W

Question

Will anything precipitate if 500.0 mL of 1.0 x 10–8 M silver(I) nitrate 500.0 mL of 2.6 x 10–5 M sodium iodide are mixed?

Question 8 options:

Q = 8.5 x 10–14, so a precipitate will form.

Q = 6.5 x 10–14, so a precipitate will form.

Q = 6.5 x 10–14, so a precipitate will not form.

Q = 2.6 x 10–14, so a precipitate will not form.

Q = 2.6 x 10–14, so a precipitate will form.

ANSWER QUESTION AND SHOW ALL THE WORK! Thanks!

Q = 8.5 x 10–14, so a precipitate will form.

Q = 6.5 x 10–14, so a precipitate will form.

Q = 6.5 x 10–14, so a precipitate will not form.

Q = 2.6 x 10–14, so a precipitate will not form.

Q = 2.6 x 10–14, so a precipitate will form.

Ksp of AgI = 8.3 x 10-17

AgI <------> Ag+ + I-

Thus both Ksp and Q have the expression as

Ksp = [Ag+][I-]

So let us calculate the [Ag=] and [I-] in the solution.

[Ag+] in the final solution = mmoles / total volume

= 500x 1.0x10-8 /1000

= 5x 10-9

[I-] in the final solution = mmoles / total volume(mL)

=500x 2.6x10-5 /1000

= 1.3 x10-5

Thus Q = [Ag+][I-]

=5x 10-9 x1.3 x10-5

= 6.5 x 10-14

As Q > Ksp a precipitate will form.

thus OPTION 2 IS CORRECT

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.