I need help with number 3 and would like to make sure my #2 Is correct. DATA TAB

Question

I need help with number 3 and would like to make sure my #2 Is correct.

DATA TABLE |Volume HCI|[NaOH]|Equivalence point!HGH,02|Volume 1[Na?Equ val (mL) (M) Volume (NaOH] trial (mL) trial HC202 (M) (mL) (mL) 12S m 0018 8 259 001 1.004 21 83 2S 004 tecinol ogY mcl 39.9 lmol DATA ANALYSIS 1. Write a reaction between sodium hydroxide and hydrochloric acid. Cas Ca4 (aa) 2.) Calculate the moles of NaOH used in the reaction with the HCI solution.(for both trials) Oely I vial 1004g N a0 40 Noot! 1.251 mol mol NoOH Calculate the molarity of the HCl solution.(for both trials) Only Tral 1 quailable 458.440mo - 02SL HC 4. Average molarity of hydrochloric acid.

Explanation / Answer

2.

Moles of NaOH = Molarity * volume at equivalence / 1000 = 1.004 * 18.86 / 1000 = 0.0189 mol

3.

From the balanced equation,

Moles of HCl = moles of NaOH = 0.0189 mol

Molarity of HCl = moles of HCl / volume of solution in L = 0.0189 / 0.025 = 0.757 M

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