Use the References to access important values if needed for this question. Consi

Question

Use the References to access important values if needed for this question. Consider the following system at equilibrium where AH AHe -198 kJ/mol, and K. -2.00-102 , at 1150 K 198 kT/mol, and K. 2.90x10, at 1150 K When 0.10 moles of SO, (g) are removed from the equilibrium system at constant temperature: The value of K The value of QeK The reaction must O run in the forward direction to restablish equilibrium. O run in the reverse direction to restablish equilibrium. e. It is already at equilibrium. The concentration of SO, wil Submit Answer

Explanation / Answer

As the concentration of reactants decreases then according to Le Chatlier's principle, the reaction will done in the way to form reactants from products

i.e, The reaction runs in the reverse direction to re-establish equilibrium.

Also in an equilibrium reaction the value of Kc doesn't change.

Hence the reaction following backward direction then Qc > Kc.

Also the concentration of SO2 decreases as the concentration of Reactant decreased and forms equilibrium again.

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