a) a ph meter is used to determine the ph of an unknown HCL solution. if the met
ID: 1039214 • Letter: A
Question
a) a ph meter is used to determine the ph of an unknown HCL solution. if the meter reads 1.80 how many moles of HCL are present in a 25 ml sample?b) how many milliliters of 0.0110 M NaOH would be needed to neutralize a 50 ml sample of the above acid to increase its pH to 7.0?
a) a ph meter is used to determine the ph of an unknown HCL solution. if the meter reads 1.80 how many moles of HCL are present in a 25 ml sample?
b) how many milliliters of 0.0110 M NaOH would be needed to neutralize a 50 ml sample of the above acid to increase its pH to 7.0?
a) a ph meter is used to determine the ph of an unknown HCL solution. if the meter reads 1.80 how many moles of HCL are present in a 25 ml sample?
b) how many milliliters of 0.0110 M NaOH would be needed to neutralize a 50 ml sample of the above acid to increase its pH to 7.0?
Explanation / Answer
a) pH = 1.8
pH = -log[H+]
[H+] = 10-pH = 10-1.8 = 0.01584893192 M
[H+] = 0.01584893192 M
0.01584893192 moles are present in 1 liter
0.01584893192 / 1000 mL = 0.00001584893 moles / mL
for 25 mL = 25 x 0.00001584893 moles / mL = 0.00039622329 moles
0.0004 moles of HCL are present in a 25 ml sample.
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b) in 50 mL of above acid moles = 50 x 0.00001584893 moles / mL = 0.0008 moles present
pH = 7.0 means complete neutralization.
HCl + NaOH --> H2O + NaCl
1 mol HCl requires 1mol NaOH
0.0008 moles acid requires 0.0008 moles NaOH
Given NaOH concentration = 0.0110M = 0.011 / 1000 mL = 0.000011 moles / mL
volume in milliliters of 0.0110 M NaOH would be needed to neutralize a 50 ml sample of the above acid to increase its pH to 7.0 = 0.0008 moles / 0.000011 moles / mL
volume in milliliters of 0.0110 M NaOH would be needed to neutralize a 50 ml sample of the above acid to increase its pH to 7.0 = 72.2 mL
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