DATA SHEET Stoichiometry: Mole Ratio Assignment Number 3 Determinations Second F

Question

DATA SHEET Stoichiometry: Mole Ratio Assignment Number 3 Determinations Second First Third Volume of 1.00M KI solution, ml Number of moles of KI Volume of 0.500M Pb(NO,)2 solution, m Number of moles of Pb(NO,) 3-OM Mass of residue, filter paper, and watch glass, Mass of filter paper, 9 Mass of watch glass, g Mass of residue, g First weighing Second weighing Mole ratlo of KI to Pb(NO) Class Data Volume Pb(NO3)2 solution, ml Number of moles of PbINO Mass of residue Laboratory assignment number 10 STOI-007

Explanation / Answer

molarity = number of moles / volume of solution (in L)

given, Molarity = 0.500M and volume = 3mL = 0.003L

So, number of moles = molarity x volume of solution = 0.500 x 0.003 moles = 0.0015moles.

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