DATA SHEET Part B: Determining the Concentration of Acetic Acid in a vinegar Sol

Question

DATA SHEET Part B: Determining the Concentration of Acetic Acid in a vinegar Solution Mass of CHscooH in the vinegar solution 5. (from label on bottle) TRIAL 1 TRIAL 2 TRIAL 3 TRIAL 4 TRIAL 5 Vol. of vinegar (val -5 -S Initial Buret vol. (v) 0.10L 21.aeL Final Buret Vol. 22L SLeek Vol. of NaOH used 21.10 L Molarity of CH3cooH -1.32M Show a sample calculation: AVE V vin, 1.32 H arity of Clls Coo H mol (1.32m 1.26m Average Molarity of CH,cooH (using best two trials) I.2em use the average molarity of vinegar to calculate the Mass of CH3CooH in the vinegar solution. (Density a 1.02 g/mL) Mass of acutie acid mass mass of acetic acid 0.37 tool, 0:02sL Mass CHaCOOH

Explanation / Answer

Calculation for mass % of acetic acid in vinegar will be as shown

Density of vinegar=1.02 g/mL

1 mL of vinegar weighs 1.02 g

So 5 mL vinegar weighs (1.02 g/mL)x5 mL=5.1 g

Molarity of acetic acid found using experiment= 1.26 M=number of moles/Volume in L

Number of moles of acetic acid=Molarityxvolume in L=1.26x5 mL/(1000 mL/L)=0.0063

Molar mass of acetic acid=2x Molar mass of C+4xMolar mass of H+2xMolar mass of O=2x12+4x1+2x16=24+4+32=60 g/mol

So mass of acetic acid in 1.26 M solution=number of molesxMolar mass=0.0063molex60g/mol=0.378 g

Mass % of acetic acid =(Mass of acetic acid/Mass of vinegar)x100 %=(0.378/5.1)x100=7.41%

So the percent error in the mass% value ={(Experimental value-given value)/Given value}x100%

={(7.41-5)/5}x100%=(2.41/5)x100=48.2%

This can be sold as table vinegar (for this content of acetic acid in vinegar varies from 5-8%)

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