a. molarity of NaOH? Equivalent Weight of an Unknown I. Data Record data in ink

Question

a. molarity of NaOH?

Equivalent Weight of an Unknown I. Data Record data in ink with units. mH0.5668 A. Molarity of NaOH B. Unknown Acid Code # C. Mass of Unknown Acid 486 1. Mass ofbeaker +aeid 2. Mass ofbeaker + acid after 1st sample 3. Mass ofbeaker + acid after 2nd sample 4. Mass of beaker + acid after 3rd sample 5. Mass of beaker acid after 4th sample 6. Mass of beaker + acid after 5th sample (if performecd) .$0680 l.997 .9842 .835c D. Buret Readings Initial Reading Endpoint Reading Volume NaOH Sample 1 Sample 2 Sample 3 Sample 4 Sample 5 0.00 r11 G?29 in 62 m 37.0 me 31.GIm 0.00me 3.80 m 32.80 mL 0.00mL 35.93 mL 35.93m (if performed) nlo un Cr-titraäsdt lost due tospillage, etc.

Explanation / Answer

Molarity (M) is the concentration of a solution defined as the number of moles of solute per liter of solution:

Molarity (M) = moles solute/liters solution

Moles of a solute can be calculated by dividing mass (g) by molar mass of the solute i.e., NaOH

Moles = mass/molar mass

The molecular molar mass of NaOH consists of the atomic masses of each atom.Thus, its molar mass involves:

MNa=22.989 g/mol

MO=15.999 g/mol

MH=1.0079 g/mol

So, its molar mass is 22.989+15.999+1.0079=39.996 g/mol

Mass of NaOH=0.5668g

Molar mass of NaOH= 39.996g/mol

Moles = mass/molar mass

=0.5668/39.996

=0.0142 mole

Molarity (M) = moles solute/liters solution

1Liter=1000 ml

=0.0142/1000

= 0.0000142M

Molarity of NaOH is 0.0000142M

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